You guys are GREAT!, question about linqdatasource
Posted: Mon 08 Sep 2008 16:51
Hi,
First i would like to mention that i am really SO HAPPY with the Devart LINQ Support product.
Q1:
In the schema modeller: Can you please tell me why there is an option "run generator for model". It seems that if i UNCHECK this, it generates a MS SQL dbml which i cannot use, because i want to use MYSQL as a database
The only way i could use the schema modeller is by checking this checkbox, so it generates classes. Without the dbml file i cannot use the linqdatasource.
Q2: When i overwrite the dbml source with the source that is generated from the option "run generator from model", the linqdatasource seems to work (for a gridview). But only when displaying a complete table. When i modify anything, (removing colums, enabling linkdatasource for automatic updates, sorting of columns) i see a message "method not supported".
Is this going to be supported in the future ? (or is it already, but maybe i do not know how to implement?)
First i would like to mention that i am really SO HAPPY with the Devart LINQ Support product.
Q1:
In the schema modeller: Can you please tell me why there is an option "run generator for model". It seems that if i UNCHECK this, it generates a MS SQL dbml which i cannot use, because i want to use MYSQL as a database
The only way i could use the schema modeller is by checking this checkbox, so it generates classes. Without the dbml file i cannot use the linqdatasource.
Q2: When i overwrite the dbml source with the source that is generated from the option "run generator from model", the linqdatasource seems to work (for a gridview). But only when displaying a complete table. When i modify anything, (removing colums, enabling linkdatasource for automatic updates, sorting of columns) i see a message "method not supported".
Is this going to be supported in the future ? (or is it already, but maybe i do not know how to implement?)